jaypee
Can Someone please solve this for me
Log2x^log2x=4
Where 2 is the base of log and exponent.
Log2x^log2x=4
Where 2 is the base of log and exponent.
arcnets-Originally posted by arcnets
lethe, I think your 1st step is invalid. I think the only answer is x=4.
well, if you saw this: cos x^{2}, what would you assume? usually, with cosine, the power takes priority. if you want the cosine function to take priority, you must write either (cos x)^{2} or cos^{2} x. so you see that normally, the exponent has higher priority in the order of operations, and i think my assumption was reasonable. i think the same argument applies to logarithms.Originally posted by arcnets
Oops!
Obviously I misinterpreted the problem. Seeing no brackets, I thought that the problem was (log2(x))^(log2(x))=4.
While lethe's solution is correct for log2(x^(log2(x)))=4.
IOW, I thought that a functional symbol (like 'log') has priority over a power. I must have been wrong.
Is there such a convention? Any comments?
This seems to be the pretty standard way of doing things and makes the most sense. I remember when I was first taking calculus and we were learning the product rule and other rules for derivatives. My teacher would always differentiate say the sine function and then multiply the derivative of what was on the inside on the right of the function instead of the left. It was very confusing for me becuase I always kept trying to make it part of the function.Originally posted by lethe
i usually write multiplications to the left of the function, to avoid ambiguity. anything multiplied on the right goes in the functions argument. so multiplication before function.