How do I solve for x in the interval [0,2pi]:(adsbygoogle = window.adsbygoogle || []).push({});

2cos(x/3)=LnX

Here's what I got:

2(.5)=LnX

1=LnX

e^(1)=x

x=2.718

is this correct?

If x=e^(Ln3)+Lne^2-5Ln1

what is x?

x=3+2-0=5

is this correct?

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# Homework Help: Logs homework help

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