Homework Help: Logs homework help

1. Sep 11, 2004

UrbanXrisis

How do I solve for x in the interval [0,2pi]:
2cos(x/3)=LnX

Here's what I got:

2(.5)=LnX
1=LnX
e^(1)=x
x=2.718
is this correct?

If x=e^(Ln3)+Lne^2-5Ln1
what is x?
x=3+2-0=5
is this correct?

2. Sep 11, 2004

Tide

Was that supposed to be $\cos \frac {\pi}{3}$?

3. Sep 11, 2004

UrbanXrisis

yes sorry, that is 2cos(pi/3)=LnX

Last edited: Sep 11, 2004
4. Sep 11, 2004

Tide

In that case, good job!

5. Sep 11, 2004

UrbanXrisis

how do I find the relative maximum value of the function y=(LnX)/X and the domain of the function Ln(X^2-1)?

6. Sep 12, 2004

Tide

Just find the derivative of the function and set it to zero.

7. Sep 12, 2004

UrbanXrisis

for the domain or for the max value?

8. Sep 12, 2004

Tide

That will give you the location of the relative maximum (you can verify that it is a maximum as opposed to a minimum). Then use that value of x that you find to determine the value of the function at that point.