- #1

Tony1

- 17

- 0

$$\int_{0}^{1}t^2\sec(t\pi)[1+\sin(t\pi)-\sin^2(t\pi)]\ln[\sin(t\pi)]\mathrm dt=\left({\pi\over 2}\right)^2-{\color{blue}{2\ln(2)\over \pi^2}}+\color{red}{{\ln^2(2)\over 2\pi}}$$