Determine the magnitude of the current through all the resistors shown in the figure The batteries have emfs of E1 = 9.00V and E2 = 12.00V and the resistors have values of R1 = 15.8Ohm , R2 = 22.3Ohm, and R3 = 34.3Ohm. maybe im just setting up my equations wrong? E2 - I3R3 - I2R2 = 0 E1 - I1R1 - I2R2 = 0 I2 = I1 + I3 so i used one equation to solve for the other unknowns, and plugged in the i2 = i1 + i3 equation in the beginning. than used that equation to solve for the final one. maybe my algebra got screwed up along the way or something. it takes like a page working through the problem only to see that you didnt get it. so solving for I1 i tried E2 -I1R1 - R2(E2 + I1R3)/(R3 + R2) = 0 which turned out to be .515 A I2: E2 - R3(I2 + [I2R2/R1]) - I2R2 = 0 which turned out to be .199 A I3: E1 - I3R3 - I3R2 - R2(E2 - I3R2)/(R1 + R2) = 0 which turned out to be .2299 A sadly they're all wrong.