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- TL;DR Summary
- I have not been able to solve this PDE; need some help pls

as you can see, z(x,y) is a function of x, y; and y is a function of x, therefore y'(x) is the total derivative of "y" respect to "x", and y"(x) is the 2nd derivative. y'(x)^2 is just the square of the derivative of y respect to x

I don't have boundary or initial conditions, so you can make up any if that simplifies finding the solution

Thank you !