- #1
Juan42
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Homework Statement
A monkey first notices a lion attacking when the lion is 12.5 m away and moving toward the monkey at a speed of 5 m/s. The monkey begins to accelerate away from the lion at 3 m/(s^2) and the lion simultaneously begins to accelerate at 2 m/(s^2). (a) How long does the monkey's escape last? (b) How far has the monkey traveled when the lion catches up with it? Answers: (a) 5 seconds; (b) 37.5 m
Homework Equations
(1) V = at + Vo
(2) V^2 = Vo^2 + 2a(X - Xo)
The Attempt at a Solution
At first I tried finding the time using the lion's information. I used (2), but I only accounted for the distance that lion traveled until it got to monkey's inital position before the monkey noticed and tried to escape the lion. I just got the answers I started with. I can't seem to know where exactly to start to find the answer that the instructor gave me. I was wondering if I could get some help with this.