(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A small ball of mass m = 0.150 kg is sliding along a frictionless loop-the-loop. The loop-the-loop is standing on a table such that the plane of the loop is vertical. The loop has a radius of r = 0.200 m. What is the magnitude of the net force acting on the ball when it is on the right side and half-way up the loop, and moving upward with a speed of 2.00 m/s?

2. Relevant equations

F=ma

Centripetal Acceleration= v^2 / r

3. The attempt at a solution

Alright, here's what I've tried:

I drew a free body diagram. Facing down, I put 9.8*.150=1.47 thinking about the gravitational force. I then used the Centripetal Acceleration equation,t (2.00^2)/.2, which resulted in 20. I then multiplied this by the mass and got 3. 3-1.47 is equal to 1.53 N, which is not the correct answer. The correct answer is 3.34 N.

Where am I going wrong?

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# Homework Help: Loop-the-Loop, net force

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