A small ball of mass m = 0.150 kg is sliding along a frictionless loop-the-loop. The loop-the-loop is standing on a table such that the plane of the loop is vertical. The loop has a radius of r = 0.200 m. What is the magnitude of the net force acting on the ball when it is on the right side and half-way up the loop, and moving upward with a speed of 2.00 m/s?
Centripetal Acceleration= v^2 / r
The Attempt at a Solution
Alright, here's what I've tried:
I drew a free body diagram. Facing down, I put 9.8*.150=1.47 thinking about the gravitational force. I then used the Centripetal Acceleration equation,t (2.00^2)/.2, which resulted in 20. I then multiplied this by the mass and got 3. 3-1.47 is equal to 1.53 N, which is not the correct answer. The correct answer is 3.34 N.
Where am I going wrong?