Hi all! First, this is neither a part of homework, university or anything like that , it is my own wondering. I have been searching a lot for how to calculate the Lorentz force acting on a single current carrying wire in Earth´s magnetic field which is 0.6 Gauss. for say a wire of voltage 12v and Current is 3A Now , I know the formula for Lorentz force is: F = q [ E + (v * B)] where F = Newtons, q = Columbs, E= Electric-field per meter, V = velocity of electron in wire. B = magnetic field in Tesla. Just first off please, Where do you take account for the distance between "the current carrying wire" and "the magnetic field". Lorentz force decreases with distance just as everything in electromagnetism, right? but I cant see or understand where do you take that in the calculation. the wire for all I know could be right above a magnet or a mile above the acting magnet...so the force would change dramatically? So: 1-Where and how do you take account for the distance between the moving charge and the magnetic field in the calculation? 2 What exactly is the "electric field volts per meter" in calculation referring to here in the calculation? 3-What would be the Lorentz force on say ordinary 12v 3A wire 1ft long ( parallel to earth surface and at sea level) in the Earths magnetic field(0.6gauss)? will the force be microscopically small or will it be visible? I will be so thankfull if I understand these a little better. Best Reagrds .