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## Homework Statement

The general gauge transformation in electrodynamics is

[tex]{\bf A}' = {\bf A} + \nabla \lambda[/tex]

and

[tex]\phi ' = \phi - {{\partial \lambda}\over{\partial t}}[/tex].

In the Lorentz gauge, we set

[tex] \nabla . {\bf A} + {{\partial \phi}\over{\partial t}} = 0 [/tex].

My question is: Is the Lorentz choice true for the tranformed potentials as well? i.e. it is true that

[tex]\nabla . {\bf A}' + {{\partial \phi '}\over{\partial t}} = 0[/tex]

## Homework Equations

## The Attempt at a Solution

I'm hoping that it is true. The freedom of the gauge transformations allows us to use either the primed potentials, or the unprimed potentials, without changing the physics (i.e. the E and B fields).