Lorentz transform for acceleration

  • Thread starter mntb
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  • #1
mntb
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derivating a from v (lorentz transform)
u is the velocity in the +x direction
u=(u-v)/(1-vu/c^2)

a=du/dt

dt=I know
du=?
 

Answers and Replies

  • #2
Dr Transport
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Differentiate [tex] v [/tex] and also [tex] t [/tex] in the Lorentz transformations, divide the equation for [tex] dv [/tex] by the equation for [tex] dt [/tex] and simplify, you should be able to get the expression for the acceleration in an accerated frame.
 

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