1. Sep 25, 2005 #1

   mntb

   

   derivating a from v (lorentz transform)
   u is the velocity in the +x direction
   u=(u-v)/(1-vu/c^2)
   
   a=du/dt
   
   dt=I know
   du=?

    

   mntb, Sep 25, 2005
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3. Sep 25, 2005 #2

   Dr Transport

   

   Science Advisor

   Gold Member

   Differentiate [tex] v [/tex] and also [tex] t [/tex] in the Lorentz transformations, divide the equation for [tex] dv [/tex] by the equation for [tex] dt [/tex] and simplify, you should be able to get the expression for the acceleration in an accerated frame.

    

   Dr Transport, Sep 25, 2005

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