- #1

- 19

- 0

u is the velocity in the +x direction

u=(u-v)/(1-vu/c^2)

du? how do you du the right side of the eq?

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- Thread starter mntb
- Start date

- #1

- 19

- 0

u is the velocity in the +x direction

u=(u-v)/(1-vu/c^2)

du? how do you du the right side of the eq?

- #2

selfAdjoint

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mntb said:

u is the velocity in the +x direction

u=(u-v)/(1-vu/c^2)

du? how do you du the right side of the eq?

What are you taking the derivative with respect to? Note that the u-time in the observed frame is not the same as the v-time in the reference frame. If you want your derivative to be Lorentz invariant you have to differentiate with respect to

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