I need to show that:(adsbygoogle = window.adsbygoogle || []).push({});

1. if E is [itex]\perp[/itex] to B in one Lorentz frame, it is [itex]\perp[/itex] in all Lorentz frames

2. [itex]|E|>|cB|[/itex] in L. frame, [itex]|E|>|cB|[/itex] in all L. frame

3. Angle b/t E and B is acute/obtuse in L. frame, it is acute/obtuse in all L. frame

4. E is [itex]\perp[/itex] to B but [itex]|E|\neq|cB|[/itex], then there is a frame which the field is purely electric or magnetic

Attempt:

1. I believe I just show that [itex] \bar{E} \cdot \bar{B} =E \cdot B[/itex]

2. I believe I just show [itex]\bar{E}^2-c^2 \bar{B}^2 =E^2-B^2c^2[/itex] so that if [itex]|E|>|cB|[/itex], then [itex]\bar{E}^2-c^2 \bar{B}^2[/itex] is positive and thus [itex]E^2-B^2c^2[/itex] has to be positive, thus, [itex]|E|>|cB|[/itex] in all frames.

Not too sure where to start for 3 and 4. Open to suggestions, also it would be great if someone could check my approach for 1 and 2. thanks.

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# Homework Help: Lorentz transformation

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