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## Homework Statement

__Before you turn away from this question: I already did most of the work, so don't be turned off by all of these words, lol. They're just my explanations.__

My main point is to get one more idea.My main point is to get one more idea.

How would you calculate the loss of energy down the ramp, given only the following information:

Mass of ball = 0.0083 kg

and

http://i1097.photobucket.com/albums/...cs_/Energy.jpg [Broken]

2. Homework Equations

2. Homework Equations

E = mgh

E = 0.5mv^2

3. The Attempt at a Solution

I already found one way:

To compare the energy at the top of the ramp, which is E = mgh and the energy at the bottom of the ramp, E2 = mgh + 0.5mv^2 and also compare E to the energy at the bottom of the projectile, E3 = 0.5mv^2.

What I'm confused about is:

when I find E1 = mgh, would I use (0.307+ 0.904) as "h" or would I just use 0.307 as "h?"

And when finding the time of the projectile in E2 using y = 0.5gt^2, would I use (0.019+0.904) as delta y?

But my main question is:

__What is another way to calculate loss of energy?__

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