I need to find the opening angle of the loss cone at a given altitude, when the magnetic latitude is 65 deg.
The Attempt at a Solution
First, I used the following equation to calculate the magnetic field at a given altitude:
B=B0/[(r/RE))*sqrt(1+3sin^2(70deg)] ; where r= 2000 km (given altitude) , B0= 3.11*10^-5 nT for Earth and RE= 6378 km (Earth's radius).
Afterwards, I use: sin^2(alfa)=B0/B and the angle I get is too big. Please, help me with this one :)