1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Lossy Inverting Integrator

  1. Mar 30, 2010 #1
    Hey guys,

    I've got this set of problems on RC/RL circuits and differentiators and integrators. I was able to solve all of them, but this one stumped me for some reason.

    Here is the problem:

    http://img31.imageshack.us/img31/4286/34370298.png [Broken]

    Relevant methods:

    1) multiplying both sides by e^(-t/RC) and differentiating?

    2) integrating, multiplying by e^(-t/RC), and isolating Vout?

    Thats the methods I used to solve the other problems, but I'm not even sure how to start on this one, so any hints would be appreciated.

    Oh, also, the solution should look something like this (i think?):

    Vout(t)=c1+(c2-c1)e^(-(t-t0)/RC) and c1,c2 are constant
     
    Last edited by a moderator: May 4, 2017
  2. jcsd
  3. Mar 30, 2010 #2

    berkeman

    User Avatar

    Staff: Mentor

    It looks like you need to differentiate both sides to get a DiffEq that you can solve...
     
    Last edited by a moderator: May 4, 2017
  4. Mar 30, 2010 #3
    Thanks for the tip. So I've tried integrating it and this is what I got:

    d/dt[Vout-Vout(t0)]=-[(A-Vout(infinity)+Vout(t0))/RC]

    Is this even correct? I'm not sure what method to use to solve this DE and I'm doubting my differentiation skills at this point. I replaced V1 with A, since it's a constant i suppose, and I moved the derivative of Vout(t0) to the left side.

    Thanks,
    Adam.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Lossy Inverting Integrator
  1. Inverting Amplifier (Replies: 3)

  2. NAND Inverter (Replies: 10)

Loading...