- #1

- 19

- 1

- Homework Statement:
- Find the lower bound of the ODE?

- Relevant Equations:
- dV/dt = 5 - 2*V(t)^(1/3)

I have following differential equation dV/dt = 5 - 2 * V(t)^(1/3) which represents a the time its take to drain a barrel of rain water which contain 25 Liter of water, at t = 0.

I am suppose to calculate the least amount of water in barrel during this process.

If I set the rate of growth to zero, meaning dV/dt = 0, then 5 - 2 * V^(1/3) = 0, and thusly V = (5/2)^(3) = 15.65, meaning the least amount of water which is in the barrel is 15.65 L,if the rate of change is zero.

But question, is this correct why at handling this problem? Because I am not really using the info, that t = 0, the barrel contains 25 L.

Any idea? On how to approach this problem differently?

I am suppose to calculate the least amount of water in barrel during this process.

If I set the rate of growth to zero, meaning dV/dt = 0, then 5 - 2 * V^(1/3) = 0, and thusly V = (5/2)^(3) = 15.65, meaning the least amount of water which is in the barrel is 15.65 L,if the rate of change is zero.

But question, is this correct why at handling this problem? Because I am not really using the info, that t = 0, the barrel contains 25 L.

Any idea? On how to approach this problem differently?