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Lowering Solubility with OH

  1. Aug 22, 2011 #1
    1. The problem statement, all variables and given/known data

    What [OH-] would lower the solubility of Mg(OH)2
    to 1.5 x 10-5 mol/L?
    Ksp is 1.5 x 10-11 for Mg(OH)2.


    2. Relevant equations

    Ksp=products/reactants

    3. The attempt at a solution

    ICE box method

    Mg OH (2) Mg(OH)2
    initial: ??? and I don't know what to do from here or even if this is the correct method to use.
     
  2. jcsd
  3. Aug 22, 2011 #2

    Borek

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    Staff: Mentor

    You don't need ICE table here, just check at what OH- concentration concentration of Mg2+ is 1.5x10-5M.
     
  4. Aug 22, 2011 #3
    1.5 x 10^-5 = [Mg(OH)2]/[Mg][OH]

    correct?
     
  5. Aug 22, 2011 #4

    Borek

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    Staff: Mentor

    Write formula for Ksp of Mg(OH)2.
     
  6. Aug 22, 2011 #5
    Ksp=products/reactants
    =[Mg(OH)2]/[Mg][OH]^2

    from the equation Mg+2OH = Mg(OH)2
     
  7. Aug 22, 2011 #6

    Borek

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    Staff: Mentor

    No, you need to reread the book. Or check some other sources.
     
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