LRC Circuit

  • Thread starter sully677
  • Start date
  • #1
6
0

Homework Statement


An L-R-C series circuit is constructed using a 175{ \Omega} resistor, a 12.5uF capacitor, and an 8.00 mH} inductor, all connected across an ac source having a variable frequency and a voltage amplitude of 25.0V

At the angular frequency in part A, find the potential difference across the ac source, the resistor, the capacitor, and the inductor at the instant that the current is equal to one-half its greatest positive value.


Homework Equations



V=IZ



The Attempt at a Solution



I found the voltage for all of them and divided by 2 since the current is half, but I can't get the right answer.
 

Answers and Replies

  • #2
Andrew Mason
Science Advisor
Homework Helper
7,692
403

Homework Statement


An L-R-C series circuit is constructed using a 175{ \Omega} resistor, a 12.5uF capacitor, and an 8.00 mH} inductor, all connected across an ac source having a variable frequency and a voltage amplitude of 25.0V

At the angular frequency in part A, find the potential difference across the ac source, the resistor, the capacitor, and the inductor at the instant that the current is equal to one-half its greatest positive value.


Homework Equations



V=IZ



The Attempt at a Solution



I found the voltage for all of them and divided by 2 since the current is half, but I can't get the right answer.
You are incorrectly assuming that the voltage and current are in phase. You have to determine the phase angle between voltage and current.

AM
 
  • #3
6
0
okay. so once the phase angle is solved for, where do you go?
 
  • #4
Andrew Mason
Science Advisor
Homework Helper
7,692
403
okay. so once the phase angle is solved for, where do you go?
Use expressions for V and I as a function of time eg.:


[tex]I = I_0\sin{(\omega t)}[/tex]

[tex]V = V_0\sin{(\omega t + \phi)}[/tex]

What is the relationship between V0 and I0? What is the value for [itex]\omega t[/itex] when I = .5I0?

AM
 

Related Threads on LRC Circuit

  • Last Post
Replies
3
Views
2K
  • Last Post
Replies
16
Views
1K
  • Last Post
Replies
18
Views
713
  • Last Post
Replies
2
Views
2K
  • Last Post
Replies
11
Views
2K
  • Last Post
Replies
11
Views
3K
  • Last Post
Replies
3
Views
1K
  • Last Post
Replies
8
Views
815
  • Last Post
Replies
1
Views
2K
  • Last Post
Replies
4
Views
2K
Top