- #1
AmagicalFishy
- 50
- 1
Hey, guys.
I'm going to start off by saying I know near nothing regarding physics and don't claim to be more than completely ignorant in anything passed the fields considered pre-calculus. I have a huge interest in particle physics, though—and have decided to take a more academically rigerous path to actually learn physics, in depth.
Anyway, my interest in the field compels me to do things like download lectures, and while I can only comprehend about 20% of the things that are over-simplified, I enjoy listening to them anyway (and try to grasp onto the few concepts that I can).
So, that is where this question is coming from. . .
Is it possible that the LSP is the graviton? If everything were to decay down to the LSP, perhaps the graviton doesn't have a super-symmetric particle—and is like the "0" in numbers (with no opposite)?
Or is that an idea that is physically impossible?
I'm going to start off by saying I know near nothing regarding physics and don't claim to be more than completely ignorant in anything passed the fields considered pre-calculus. I have a huge interest in particle physics, though—and have decided to take a more academically rigerous path to actually learn physics, in depth.
Anyway, my interest in the field compels me to do things like download lectures, and while I can only comprehend about 20% of the things that are over-simplified, I enjoy listening to them anyway (and try to grasp onto the few concepts that I can).
So, that is where this question is coming from. . .
Is it possible that the LSP is the graviton? If everything were to decay down to the LSP, perhaps the graviton doesn't have a super-symmetric particle—and is like the "0" in numbers (with no opposite)?
Or is that an idea that is physically impossible?