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M/s^3 to m/s^2

  1. Oct 6, 2014 #1
    1. The problem statement, all variables and given/known data
    distance= z + b*time + x*(time^2) + y*(time^3)

    x=0,2m/s^2
    y=0,15m/s^3

    I have to calculate after how long time the speed has increased by 10 m/s


    3. The attempt at a solution
    I have no idea what to do with m/s^3
     
    Last edited: Oct 6, 2014
  2. jcsd
  3. Oct 6, 2014 #2

    SteamKing

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    Your problem statement is unclear.

    Please post the complete and exact wording of the problem, as it appears in your text or was otherwise supplied to you.
     
  4. Oct 6, 2014 #3
    Yeah, sorry, I didn't write the formula correctly that was given in this exercise.. I edited the OP.
    distance= z + b*time + x*(time^2) + y*(time^3)

    z is some distance
    b is starting speed

    I have really bad English when it comes to terminology, so I hope you can understand now.
     
  5. Oct 6, 2014 #4

    Orodruin

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    How is the velocity related to the distance travelled?
     
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