M0re frict0n (1 Viewer)

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1. The problem statement, all variables and given/known data
Man pushes a box that is 11.2 kg on a horizontal surface at a constant speed of 3.5 m/s2. Where μ is .20
a)What is the horizontal force rthat teh man must apply to maintain teh motion
b)If the force of part a is removed, how far does the box slide before coming to rest?

2. Relevant equations
F=ma
F=μN


3. The attempt at a solution
F=ma
F=11.2(3.5)
F=39.2

then
F=μN
F=(.20)(109.76)... [11.5*9.8]
F=21.95

then to get the total force i added 39.2+21.95 and got a total of 61.152

For part b I would asume that without part a the force would just be 21.95 because it doesnt account for the answerr to part a?
 

rl.bhat

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Man pushes a box that is 11.2 kg on a horizontal surface at a constant speed of 3.5 m/s2

Constant speed or acceleration?
 

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