i have trouble expandind f(x)= (sin2x)^2 into Maclaurin series(adsbygoogle = window.adsbygoogle || []).push({});

for sin(x) Maclaurin series is

[tex]\sum^{\infty}_{n=0} (-1)^n \frac{x^{2n+1}}{(2n+1)!} [/tex]

probably the key is to change (sin2x)^2 into new shape. I found that

(sin2x)^2=2sin(2x^2), but that coefficent 2 is bothering me, what to do?

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# Maclaurin series help

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