- #1

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solved thanks

Last edited:

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- Thread starter irunshow
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- #1

- 19

- 0

solved thanks

Last edited:

- #2

Dick

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- #3

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Yea my teacher didnt explain it in class cause there was no time left.

Is there a general formula to calculate the max error?

Thanks

- #4

Dick

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- #5

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thanks but i think my teachers wants to do it with this formula:

abs(Rn(x)) less than or equal to (M)/(n+1)! abs(x-a)^(n+1)

I dont know what the M equals to tho

- #6

Dick

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thanks but i think my teachers wants to do it with this formula:

abs(Rn(x)) less than or equal to (M)/(n+1)! abs(x-a)^(n+1)

I dont know what the M equals to tho

M is a bound for the k+1 derivative of f(x) over the interval. Look at the link I sent you. You'll see f^(k+1) instead of M.

- #7

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Hi i got the answer to be 0.0317.

Is that correct?

Thanks =)

Is that correct?

Thanks =)

- #8

Dick

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solved thanks

Don't delete the problem after you've solved it! Other people with similar problems are supposed to be able to search for previous threads that can help them. Deleting parts of it defeats that.

- #9

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edit: kk i wont next time xD

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