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1/(1+x^2)=1-x^2 + x^4-x^6+....+(-1)^n(x^2n)+.... -1 > x > 1
how to get this??.....
how to get this??.....
If you do not want to go all the way to the general theory of series of powers (Taylor and MacLaurin series), you can simply use the result of the geometric seriesOriginally posted by newton1
1/(1+x^2)=1-x^2 + x^4-x^6+....+(-1)^n(x^2n)+.... -1 > x > 1
how to get this??.....