Magnet Field of a Solenoid: Understanding the Derivation Step by Step

In summary, the problem statement discusses a problem involving setting ρ equal to the hypotenuse in a triangle. The attempt at a solution involves finding the derivative of dl in terms of ρ and θ. However, there is a discrepancy between the given equation and the result obtained through differentiation. The conversation ends with a suggestion to differentiate cotθ.
  • #1
zezima1
123
0

Homework Statement


Attached file shows the problem statement.

The Attempt at a Solution


I can do this problem easily. Problem is that there's just one step in my book's derivation that I don't understand. It sets ρ equal to the hypotenuse in the triangle and then says that:

dl = ρ/sinθ dθ (1)

For some reason I can't get this result. If we look at the cosine of θ then:
cosθ = l/ρ
=>
l = ρcosθ
=>
dl/dθ = -ρsinθ
=>dl = -ρsinθdθ

Incosistent with (1). What am I doing wrong?
 
Physics news on Phys.org
  • #2
hi zezima1! :smile:
zezima1 said:
… It sets ρ equal to the hypotenuse in the triangle and then says that:

dl = ρ/sinθ dθ (1)

For some reason I can't get this result. If we look at the cosine of θ then:
cosθ = l/ρ
=>
l = ρcosθ
=>
dl/dθ = -ρsinθ
=>dl = -ρsinθdθ

ah, but ρ isn't constant, h is …

differentiate cotθ = l/h :wink:
 

What is a solenoid?

A solenoid is a coil of wire that is used to create a magnetic field.

How does a solenoid create a magnetic field?

When an electric current passes through the wire of a solenoid, it creates a magnetic field around the coil.

What is the direction of the magnetic field in a solenoid?

The magnetic field in a solenoid is in the same direction as the current flowing through the coil.

How does the strength of the magnetic field in a solenoid vary?

The strength of the magnetic field in a solenoid is directly proportional to the number of turns in the coil, the current flowing through the coil, and the permeability of the material inside the coil.

What are some common applications of solenoids?

Solenoids are commonly used in electromagnets, electric motors, relays, and various other electronic devices. They are also used in industrial applications such as door locks, valves, and actuators.

Similar threads

  • Advanced Physics Homework Help
Replies
5
Views
1K
Replies
5
Views
1K
  • Introductory Physics Homework Help
Replies
4
Views
320
  • Advanced Physics Homework Help
Replies
4
Views
3K
  • Advanced Physics Homework Help
Replies
1
Views
2K
  • Advanced Physics Homework Help
Replies
3
Views
2K
  • Advanced Physics Homework Help
Replies
1
Views
2K
  • Calculus
Replies
9
Views
1K
  • Engineering and Comp Sci Homework Help
Replies
20
Views
2K
  • Advanced Physics Homework Help
Replies
7
Views
3K
Back
Top