It's much easier to get v from your solution for i by using vBl = Ldi/dt.
That is how I got displacement in post#23 .
v = (Limcosωt)/(Blω)
Now putting v = dx/dt and integrating I get the expression for displacement .
Now in the expression v = (Limcosωt)/(Blω) , if I put t=0 , I get v0 = (Lim)/(Blω) which I think is correct value of v0 .
But from the expression v = v0 + (Biml)(cosωt-1)/(mω) , how do we get value of v0 ?
I am trying to find value of v0 from the expression of v of post#24 .