- #26

- 971

- 40

It's much easier to get v from your solution for i by using vBl = Ldi/dt.

That is how I got displacement in post#23 .

v = (Li

_{m}cosωt)/(Blω)

Now putting v = dx/dt and integrating I get the expression for displacement .

Now in the expression v = (Li

_{m}cosωt)/(Blω) , if I put t=0 , I get v

_{0}= (Li

_{m})/(Blω) which I think is correct value of v

_{0}.

But from the expression v = v

_{0}+ (Bi

_{m}l)(cosωt-1)/(mω) , how do we get value of v

_{0}?

I am trying to find value of v

_{0}from the expression of v of post#24 .