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## Homework Statement

A 0.49 m copper rod with a mass of 0.13 kg carries a current of 10 A in the positive x direction. Let upward be the positive y direction.

1) What is the magnitude of the minimum magnetic field needed to levitate the rod?

2) What is the direction of the minimum magnetic field needed to levitate the rod?

pos x direction, neg x, pos y, neg y, pos z, neg z

## Homework Equations

Right Hand Rule?

## The Attempt at a Solution

I figured out part 1 but not sure on part two. any guidance would be appreciated. I'm thinking it's positive y direction. Part 1 answer was B = .26 T fwiw