A 0.49 m copper rod with a mass of 0.13 kg carries a current of 10 A in the positive x direction. Let upward be the positive y direction.
1) What is the magnitude of the minimum magnetic field needed to levitate the rod?
2) What is the direction of the minimum magnetic field needed to levitate the rod?
pos x direction, neg x, pos y, neg y, pos z, neg z
Right Hand Rule?
The Attempt at a Solution
I figured out part 1 but not sure on part two. any guidance would be appreciated. I'm thinking it's positive y direction. Part 1 answer was B = .26 T fwiw