Figure 29-48 shows two very long straight wires (in cross section) that each carry a current of
4.00 A directly out of the page. Distance d1 = 6.00 m and distance d2 = 4.00 m. What is the magnitude of the net magnetic field at point P, which lies on a perpendicular bisector to the wires?
- B = (μ*i)/(2*π*r)
Again struck up with the direction of the magnetic field, i suppose now the field not simple along the x axis. How to find the angle and the direction of the field. My attempt is
B1 = (μ*i)/(2*π*r) = (4*π*4)/(2*π*4) = 200nT where r = d2 = 4; is the field due to i1.
B2 = (μ*i)/(2*π*r) = (4*π*4)/(2*π*4) = 200nT where r = d2 = 4; is the field due to i2.
B1 and B2 are making an angle of 90° between them (not convinced either). The net field is √(B1^2 + B2^2 = 282 nT.