- #1
Physicslearner500039
- 124
- 6
- Homework Statement
- One long wire lies along an x axis and carries a current of 30A in the positive x direction. A second long wire is perpendicular to the xy plane, passes through the point (0,4.0 m, 0), and carries a current of 40 A in the positive z direction. What is the magnitude of the resulting magnetic field at the point (0,2.0 m, 0)?
- Relevant Equations
- Magnetic field due to long wire (μ0*i)/(2*π*r)
The problem is as above, My attempt is as below but there is lot of effort in terms of imagining and not very confident,
Required the magnetic field on the y-axis let us say point P.
The magnetic field due to the x-axis wire is out of the paper at P with the values as R=2.0m, i =30A.
B1 = (μ0*i)/(2*π*r) = (4*π*(10^-7)* 30)/(2*π*2) = 3uT,
For the Z axis wire the magnetic field is again into the paper at P with the values as R=2.0m, i = 40A
B2 = (μ0*i)/(2*π*r) = (4*π*(10^-7)* 40)/(2*π*2) = 4uT. The resultant is 1uT. The answer does not seem to match it is 5uT. Please advise.