I need to do the following integral:(adsbygoogle = window.adsbygoogle || []).push({});

[itex]B_z=\frac{\mu_0 I N a^2}{2} \int_{0}^{L} (a^2+(z-z')^2)^{-\frac{3}{2}} dz'[/itex]

so far i have set [itex]x=z-z' \Rightarrow dx=-dz'[/itex] and the limits also change to give

[itex]B_z = - \frac{\mu_0 I N a^2}{2} \int_{z}^{z-L} \frac{dx}{(a^2+x^2)^{\frac{3}{2}}}=\frac{\mu_0 I N a^2}{2a^3} \int_{z-L}^{z} \frac{dx}{(1+(\frac{x}{a})^2)^{\frac{3}{2}}}[/itex]

im having trouble with the power of 3/2 as otherwise its just a standard integral to arctan. any advice?

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Magnetic Field Integral

**Physics Forums | Science Articles, Homework Help, Discussion**