I need to do the following integral:(adsbygoogle = window.adsbygoogle || []).push({});

[itex]B_z=\frac{\mu_0 I N a^2}{2} \int_{0}^{L} (a^2+(z-z')^2)^{-\frac{3}{2}} dz'[/itex]

so far i have set [itex]x=z-z' \Rightarrow dx=-dz'[/itex] and the limits also change to give

[itex]B_z = - \frac{\mu_0 I N a^2}{2} \int_{z}^{z-L} \frac{dx}{(a^2+x^2)^{\frac{3}{2}}}=\frac{\mu_0 I N a^2}{2a^3} \int_{z-L}^{z} \frac{dx}{(1+(\frac{x}{a})^2)^{\frac{3}{2}}}[/itex]

im having trouble with the power of 3/2 as otherwise its just a standard integral to arctan. any advice?

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# Homework Help: Magnetic Field Integral

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