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Physics
Classical Physics
Electromagnetism
Magnetic field outside a solenoid
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[QUOTE="Charles Link, post: 6265219, member: 583509"] The magnetic surface currents from a cylinder of uniform magnetization have the same geometry as the currents of a solenoid. In practice, any solenoid will also have a current ## I ## going in the ## z ## direction along its axis, but this is usually ignored in any textbook treatment of the magnetic field of a solenoid. You are correct=this will generate a ## \phi ## component of the magnetic field, but it is normally ignored.## \\ ## (Edit: There will, in general, also be a magnetic field generated by the current in the wires leading to the solenoid, but these are also not included in the computation, since they will be depend on the particular geometry). ## \\ ## For Griffith's choice of a magnetized cylinder, perhaps he wanted to introduce the reader to the concept of a permanent magnet that has a cylindrical shape. It can be modeled as having uniform magnetization. There is also a "pole" model for computing the magnetic field ## B ## from the magnetized cylinder, which gets identical results as the magnetic surface current computation. See [URL]https://www.physicsforums.com/threads/a-magnetostatics-problem-of-interest-2.971045/[/URL] [/QUOTE]
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Magnetic field outside a solenoid
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