- #1

Kennedy111

- 27

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## Homework Statement

An electron (m= 9.11 x 10^-31 kg) enters a downward magnetic field of 5.00 x 10^-1 T with a velocity of 6.50 x 10^6 m/s West. Calculate the radius of the circular path it will follow when it is traveling within the magnetic field.

m = 9.11 x 10^-31 kg

v = 6.50 x 10^6 m/s West

B = 5.00 x 10^-1 T

q = -1.60 x 10^-19 C

## Homework Equations

Fm = qvB

Fc = mv^2/r

Fm = Fc

## The Attempt at a Solution

Fm = qvB

= (1.60 x 10^-19 C)(6.50 x 10^6 m/s)(5.00 x 10^-1 T)

= 5.2 x 10^-13 N

Fm = mv^2/r

r = mv^2/Fm

= (9.11 x 10^-31 kg)(6.50 x 10^6 m/s)^2 / (5.2 x 10^-13 N)

= 7.40 x 10^-5 m

I feel like I may have done this question wrong...