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Magnetic field question

  1. Mar 29, 2008 #1
    1. The problem statement, all variables and given/known data

    What is the minimum radius of curvature for an alpha particle, He, moving at 2.0x10^-6m/s in a magnetic field of 2.9x10^-5T?

    2. Relevant equations

    F=qvBsin(theta)...then F=BILsin(theta)

    3. The attempt at a solution

    F=qvBsin(theta)
    =(1.602x10^-19)(2.0x10^6)(2.9x10^-5T)sin90
    =9.2916x10^-18

    F=BILsin(theta)......
     
  2. jcsd
  3. Mar 29, 2008 #2

    G01

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    Homework Helper
    Gold Member

    You have a value for the Magnetic Force on the particle, but no you need to somehow relate that value to the radius of the particles trajectory in order to find your answer.

    HINT:

    The magnetic force is making the particle move in a circle. So, what type of force does that make it?
     
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