An antiproton (same properties as a proton except that q=-e) is moving in the combined electric and magnetic fields of the figure
The antiproton is moving to the right with a velocity of 500m/s the magnetic field B=2.5T is coming into the page and E=1000V/m downward.
What is the magnitude of the antiproton's acceleration at this instant?
The Attempt at a Solution
The answer is 2.4x10^10m/s^2. I bascially went ma=qvB which didn't work. I'm not sure why it shows E.