1. The problem statement, all variables and given/known data A proton travels horizontally with speed 4.0E6 m/s in a vertical uniform magnetic field of 1.5 tesla. Determine the magnitude of proton's acceleration. Describe it' s path. 2. Relevant equations F=qvB F=ma Mass of proton=1.67E-27kg Charge of proton=1.60E-19C 3. The attempt at a solution This is what I did and want to know if I am thinking correctly. F=qvB F=(1.6E-19C)(4.0E6m/s)(1.5T) F=9.6E-13 then I used newtons 2nd Law to solve for acceleration F=ma a=F/m a=9.6E13N/1.67E-27kg a=5.752E14 Is my thought process correct? Or am I completely confused? Thanks for the help!