A 3.60 mC charge moving at 862 m/s travels at right angles to a magnetic field, and experiences a .00425 N magnetic force. Find the strength of the magnetic field. F = qvB (not sure if the right angle makes a difference in the equation.) B= .00425 /(3.60x10^-6)(862) = 1.37 T A 53.0 mC charge is now moving at 1300 m/s and 550 to the same magnetic field. Find the magnetic force exerted on the second charge. F = (53x10^-6C) (1300m/s)(550T) = 37.8 N Does this look correct? Also, I am wondering what if the angle was not a right angle? how would that differ the equation I would use..