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By direct integration show that for any arbitrary loop carry a current i

[tex] F = \oint idL \cross B = 0 [/tex]

Note that an arbitrary current loop doesn ot need to lie in a plane

WEll since that is true then both dL and d(theta) are integration varaibles here

should something like this be formed?

[tex] B \int_{0}^{L} \int_{\theta_{1}}^{\theta_{2}} \sin(\theta)dL + L \cos(\theta) d\theta [/tex]

am i right? I m not sure about the limits of integration tho...

please advise

thank you

[tex] F = \oint idL \cross B = 0 [/tex]

Note that an arbitrary current loop doesn ot need to lie in a plane

WEll since that is true then both dL and d(theta) are integration varaibles here

should something like this be formed?

[tex] B \int_{0}^{L} \int_{\theta_{1}}^{\theta_{2}} \sin(\theta)dL + L \cos(\theta) d\theta [/tex]

am i right? I m not sure about the limits of integration tho...

please advise

thank you

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