1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Magnetic Field

  1. Nov 15, 2005 #1
    By direct integration show that for any arbitrary loop carry a current i
    [tex] F = \oint idL \cross B = 0 [/tex]
    Note that an arbitrary current loop doesn ot need to lie in a plane
    WEll since that is true then both dL and d(theta) are integration varaibles here
    should something like this be formed?
    [tex] B \int_{0}^{L} \int_{\theta_{1}}^{\theta_{2}} \sin(\theta)dL + L \cos(\theta) d\theta [/tex]
    am i right? I m not sure about the limits of integration tho...

    please advise

    thank you
     
    Last edited: Nov 15, 2005
  2. jcsd
  3. Nov 15, 2005 #2

    Physics Monkey

    User Avatar
    Science Advisor
    Homework Helper

    Is the magnetic field constant? If so, doesn't the force on a closed loop equal
    [tex]
    \vec{F} = I \oint d\vec{\ell} \times \vec{B},
    [/tex]
    which reduces to
    [tex]
    \vec{F} =\left( I \oint d\vec{\ell} \right) \times \vec{B},
    [/tex]
    since the magnetic field is constant. What is
    [tex]
    \oint d\vec{\ell} \,\,?
    [/tex]
     
    Last edited: Nov 15, 2005
  4. Nov 15, 2005 #3
    [tex] \oint dL = 0 [/tex] because of Green's Theorem??

    In my calc text book it says that [tex]\int_{C} \nabla f = o [/tex] for any piecewise differentiable curve?
     
    Last edited: Nov 16, 2005
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: Magnetic Field
  1. Magnetic field (Replies: 4)

  2. Magnetic Field (Replies: 0)

Loading...