Magnetic Field (1 Viewer)

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

By direct integration show that for any arbitrary loop carry a current i
[tex] F = \oint idL \cross B = 0 [/tex]
Note that an arbitrary current loop doesn ot need to lie in a plane
WEll since that is true then both dL and d(theta) are integration varaibles here
should something like this be formed?
[tex] B \int_{0}^{L} \int_{\theta_{1}}^{\theta_{2}} \sin(\theta)dL + L \cos(\theta) d\theta [/tex]
am i right? I m not sure about the limits of integration tho...

please advise

thank you
 
Last edited:

Physics Monkey

Science Advisor
Homework Helper
1,364
34
Is the magnetic field constant? If so, doesn't the force on a closed loop equal
[tex]
\vec{F} = I \oint d\vec{\ell} \times \vec{B},
[/tex]
which reduces to
[tex]
\vec{F} =\left( I \oint d\vec{\ell} \right) \times \vec{B},
[/tex]
since the magnetic field is constant. What is
[tex]
\oint d\vec{\ell} \,\,?
[/tex]
 
Last edited:
[tex] \oint dL = 0 [/tex] because of Green's Theorem??

In my calc text book it says that [tex]\int_{C} \nabla f = o [/tex] for any piecewise differentiable curve?
 
Last edited:

The Physics Forums Way

We Value Quality
• Topics based on mainstream science
• Proper English grammar and spelling
We Value Civility
• Positive and compassionate attitudes
• Patience while debating
We Value Productivity
• Disciplined to remain on-topic
• Recognition of own weaknesses
• Solo and co-op problem solving
Top