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Homework Help: Magnetic field

  1. Nov 19, 2005 #1
    does anybody know why the magnetic field for a single-layer solenoid of a point in the middle of the solenoid axial field is
    H=[(4pini)/(10L)]*{[L+2x/[2(D^2+(L+2x)^2]^(0.5) +
    [L-2x/[2(D^2+(L-2x)^2]^(0.5)}
    where L is the length of a finite solenoid, D is the diameter
     
  2. jcsd
  3. Nov 19, 2005 #2

    Physics Monkey

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    You can calculate the on axis magnetic field of a current loop. To obtain the on axis field of a finite solenoid, just integrate.
     
  4. Nov 20, 2005 #3
    i did.... i'm stuck on where does[(4pini)/(10L)] come from?
     
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