(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

An ion of charge 1.6 x 10^(-19) C and Kinetic energy 2.0k eV enters perpendicularly into a uniform magnetic field .The ion performs a circular path of radius 4.3 cm .Determine the mass of the ion if the magnetic field intensity is 0.5 T.

2. Relevant equations

3. The attempt at a solution

1/2 mv^2 = 2.0 x 10^3

mv^2 = 4.0 x 10^3 ---1

(mv^2)/r=Bev

mv = (0.5)(1.6 x 10^(-19))(0.043)

v = [3.44 x 10^(-21) ]/m ---2

Sub 2 into 1 ,

m{[3.44 x 10^(-21) ]/m }=4.0 x 10^3

Solve for m , i got a very small figure which is wrong .

THe correct answer is 1.84 x 10^(-26) kg

where did i go wrong ?

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# Homework Help: Magnetic field

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