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Magnetic field

  1. Aug 26, 2010 #1
    1. The problem statement, all variables and given/known data

    In Vermont the dip angle for the earth's magnetic field(the angle the field lines make with the horizontal) is 74 degree and the component of the field parallel to the earth's surface is 0.16G. If an electron is shot with a speed 10^6 m/s vertically upward there, how large a force acts on the electron and what is the direction of the force? How large an acceleration will this force cause?

    Repeat the problem if the electron is shot horizontally northward.

    mass of electron = 9.1 x 10^(-31) kg and 1G=10^(-4)T

    2. Relevant equations

    3. The attempt at a solution

    some hints to get me started. Thanks.
  2. jcsd
  3. Aug 26, 2010 #2
    Try using F = qv x B
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