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Two oppositely charged objects exert a force of attraction of 8.0N on each other. What will be the new force of attraction if the objects are moved to a diustance four times their original distance of separation?

i did this..

F=kq1*q2/4r

8.0N=9.0x10^9 (1)(1)/4r

r=1.125x10^9m

how can you find the new force...HELP.. i dont know wat to do next here...

the right answer in my book is 0.50N.

i did this..

F=kq1*q2/4r

8.0N=9.0x10^9 (1)(1)/4r

r=1.125x10^9m

how can you find the new force...HELP.. i dont know wat to do next here...

the right answer in my book is 0.50N.

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