1. The problem statement, all variables and given/known data An electron is moving through a magnetic field whose magnitude is 9.10x10^-4 T. The electron experiences only a magnetic force and has an acceleration of magnitude 3.60x10^14 m/s^2. At a certain instant, it has a speed of 6.30x10^6 m/s. Determine the angle (less than 90°) between the electron's velocity and the magnetic field. 2. Relevant equations Magnetic Force F = qvBsin(theta) F=ma 3. The attempt at a solution F=ma --> mass of electron x acceleration = 3.27x10^-16N F = qvBsin(theta) 3.27x10^-16N / [(charge of electron) x (6.30x10^6 m/s) x (9.10x10^-4 T)] = sin (theta) solving like this would make sin theta = 3.56 x 10^11, which is not reasonable at all....What am i doing wrong?