# Magnetic Fields, Find Angle

1. Jul 15, 2008

### kdrobey

1. The problem statement, all variables and given/known data
Due to friction with the air, an airplane has acquired a net charge of 1.70 multiplied by 10-5 C. The plane moves with a speed of 2.80 multiplied by 102 m/s at an angle θ with respect to the earth's magnetic field, the magnitude of which is 5.00 multiplied by 10-5 T. The magnetic force on the airplane has a magnitude of 2.30 multiplied by 10-7 N. Find the angle θ. (There are two possible angles.)
________(smaller angle)
________(larger angle)

2. Relevant equations

B=F/QoVsin(angle)

3. The attempt at a solution
I got Sin(angle)=F/QoVB, and arrived at sing(angle)=.966, which gave me the smaller angle 75.1, how do you get the larger angle?

2. Jul 15, 2008

### alphysicist

Hi kdrobey,

I don't think you'll be able to get it with your calculator; you'll have to think about the behavior of the sine function.

For example, the sine of 150 degrees is (1/2). But if you find the inverse sine of (1/2), the calculation won't return 150 degrees.

Does that help? What do you get for your larger angle in this problem?