- #1

athenaroa

- 11

- 0

You are using an out of date browser. It may not display this or other websites correctly.

You should upgrade or use an alternative browser.

You should upgrade or use an alternative browser.

- Thread starter athenaroa
- Start date

- #1

athenaroa

- 11

- 0

- #2

Chen

- 977

- 1

The magnetic force on a charge that travels through a magnetic field is:

[tex]\vec F_m = q\vec V \times \vec B = q|V||B|\sin \alpha[/tex]

([itex]\alpha[/tex] being the angle between the field vector and the velocity vector of course.)

[tex]\vec F_m = q\vec V \times \vec B = q|V||B|\sin \alpha[/tex]

([itex]\alpha[/tex] being the angle between the field vector and the velocity vector of course.)

Last edited:

- #3

- 35,995

- 4,714

Originally posted by Chen

The magnetic force on a charge that travels through a magnetic field is:

[tex]\vec F_m = q\vec B \times \vec V = q|B||V|\sin \alpha[/tex]

([itex]\alpha[/tex] being the angle between the field vector and the velocity vector of course.)

I normally would not be picky on such things. However, it should be corrected that the general form of Lorentz force for the magnetic field term is proportional to q(v x B), not q(B x v).

Since the original question involves the exact vectorial direction of the force, and since cross products are not commutative, this can produce an error in the direction.

Zz.

- #4

Chen

- 977

- 1

Share:

- Replies
- 11

- Views
- 154

- Replies
- 9

- Views
- 391

- Replies
- 4

- Views
- 243

- Last Post

- Replies
- 1

- Views
- 310

- Replies
- 16

- Views
- 348

- Replies
- 7

- Views
- 359

- Last Post

- Replies
- 1

- Views
- 123

- Last Post

- Replies
- 30

- Views
- 1K

- Replies
- 41

- Views
- 991

- Replies
- 9

- Views
- 454