# Magnetic flux help (1 Viewer)

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#### jimmy_neutron

I have a question dealing with magnetic flux that I cannot seem to get. Please help

Question= A 2m conductor is formed into a square and placed in the xy plane. a magnetic field is oriented 30 degrees above the horizontal with a strength of 6T. What is the magnetic flux through the conductor?
I would solve this by using the equation: Flux = BAcos(theta) = (6T)(2^2)cos30 = 20.8
however this answer is incorrect. can anyone tell me what im doing wrong
thanks!

#### Tide

Homework Helper
I think you want the angle the field makes with the normal to the plane of the square - not 30 degrees.

#### jimmy_neutron

ok, can you help me find the angle needed for the equation.

#### Hootenanny

Staff Emeritus
Gold Member
I would draw a diagram. Draw the plane as a horizontal line, then draw in the normal. Next draw in a line representing the magnetic field, lable the angle between the magnetic field and the plane. You want the angle between the magnetic field and the normal.

Hope this helps #### Da-Force

Theta would be the angle between the Field and the Area Vector.

Try using your hands :-)

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