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Magnetic Flux in a Solenoid

  1. Oct 10, 2015 #1
    1. The problem statement, all variables and given/known data
    A single-turn square loop of side L is centered on the axis of a long solenoid. In addition, the plane of the square loop is perpendicular to the axis of the solenoid. The solenoid has 1280 turns per meter and a diameter of 5.85 cm , and carries a current of 2.15 A .

    Find the magnetic flux through the loop when L= 5.85 cm .

    2. Relevant equations
    Magnetic Field = 4pi *10^-7 * (Num loops/ length) * current
    Magnetic Flux = Magnetic Field * Area * cos(theta)

    3. The attempt at a solution
    Magnetic Field = 4pi *10^-7 * (1280 loops/ 1.00m) * 2.15A = 0.003458T
    Magnetic Flux = B * area = 0.003458 * 0.0585 * 0.0585 = 1.18x10-5

    The answer is wrong, I would appreciate any help! Thanks!
     
  2. jcsd
  3. Oct 10, 2015 #2
    Why are you put the length as ## 1.00m##?
     
  4. Oct 10, 2015 #3
    Because the question says 1280 turns per meter
     
  5. Oct 10, 2015 #4
    Here the area is maybe the area of solenoid, isn't it?
     
  6. Oct 10, 2015 #5
    You are right! Thanks
     
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