1. The problem statement, all variables and given/known data A wire circle of radius 0.050 m is embedded in a solenoid of length 0.20 m with 1000 turns that carries a current of 0.50 A. If a vector that is normal to the plane of the circle makes a 40° angle with the axis of the solenoid, what is the magnetic flux through the loop? 2. Relevant equations B (solenoid) = μ*I*n Flux = B*A*cosθ 3. The attempt at a solution n=1000/.2 I'm using the loops per unit length l=.20m r=0.05m I=0.5A I plugged in the values to solve for the magnetic field: B=(4*∏*10^-7)*(0.5A)*(1000/.2) B=0.031T A=(∏r^2)*(l) A=1.5e-4 m^3 I'm having some trouble visualizing the angle, but I think the angle should be 50? Can someone point me in the right direction?