1. The problem statement, all variables and given/known data An electron in a vacuum is first accelerated by a voltage of 48200 V and then enters a region in which there is a uniform magnetic field of 0.183 T at right angles to the direction of the electron's motion. What is the force on the electron due to the magnetic field? 2. Relevant equations F = qvBsintheta 3. The attempt at a solution U = Vq (potential energy) 1/2 mv^2 (kinetic energy) I set potential energy equal to kinetic energy to solve for velocity. Vq = 1/2 mv^2 (then solve for v) v = SQRT(2qv/m) F = qB(SQRT(2qv/m))sintheta Plugging in the numbers, I get F = (1.6e-19) (0.183T) (SQRT(2(1.6e-19)*48200V/9.11e-31))* sin (90) F = 3.82 e -12 Is this the right way to do this problem? Thanks in advance for looking it over for me.