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Magnetic Force Per Unit Length

  1. Oct 23, 2008 #1
    1. The problem statement, all variables and given/known data
    A packed bundle of 100 long, straight, insulated wires forms a cylinder of radius R = 0.600 cm.

    If each wire carries 4.50 A, what are the magnitude and direction of the magnetic force per unit length acting on a wire located 0.200 cm from the center of the bundle?

    2. Relevant equations
    [tex]F/L = IB [/tex]
    [tex]B = (\frac{(\mu)I}{2(\pi)R^{2}})r [/tex]

    3. The attempt at a solution

    I plugged in the various values getting:

    [tex]F/L = (450)((4\pi X 10^{-7}*450)/(2\pi(.006^{2}))(.002)[/tex]

    That equals 2.25 N/m which is orders of magnitude off. Can anyone tell me what I am doing wrong here? This problem is in the book with slightly different numbers and the answer is is X.XX mN/m. Thanks for the help.
    Last edited: Oct 23, 2008
  2. jcsd
  3. Oct 23, 2008 #2
    Anyone know where I am going wrong?
  4. Oct 25, 2008 #3


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    Homework Helper

    Hi Ithryndil,

    I don't think this is correct. The B-field part looks right to me, but if you then compare this to your first equation F/L = IB, this would be the force per unit length on a single wire that has a current of 450A.
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