(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A wire of length 95m and a diameter of 2.4mm has a total resistance 1.59Ohms. The potential difference between the ends of the wire is 103volts. A section of the wire 15.5cm in length is bent into an arc of 60deg. The magnetic field is parallel to the bisector of the arc and has a strength of B=1.4T . What is the magnitude of the magnetic force on the arc of wire?

2. Relevant equations

F = I*l*B*sin(Phi)

3. The attempt at a solution

I found the current by solving I = V/R which gives me 64.78 Amps.

Now the part I'm having trouble with is finding out the magnetic field that is parallel to the bisector of the arc. I don't think I understand this questionThe magnetic field is parallel to the bisector of the arc and has a strength of B=1.4T .

What are your suggestion on this one? And fyi, my teacher didn't lecture this topic yet, but the reason I want to do HW early is to have more time to study this so I can get good grade on the next test.

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# Homework Help: Magnetic Forces with Currents

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